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authorsijanec <anton@sijanec.eu>2021-02-14 14:00:50 +0100
committersijanec <anton@sijanec.eu>2021-02-14 14:00:50 +0100
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diff --git a/mat/domace_naloge/25/dokument.tex b/mat/domace_naloge/25/dokument.tex
index 5985914..e4e67e0 100644
--- a/mat/domace_naloge/25/dokument.tex
+++ b/mat/domace_naloge/25/dokument.tex
@@ -151,9 +151,9 @@ Ta dokument vsebuje navodila in rešitve domačih nalog snovi \textit{\snovdn}pr
\item $$\frac{\sin\ang{210}-\cos\ang{270}}{\tan\ang{135}\cdot\cot\ang{315}-\sin\ang{300}}
=\frac{-\sin\ang{30}-0}{\frac{\sin{135}}{\cos{135}}\cdot\frac{\cos\ang{315}}{\sin\ang{315}}+\sin\ang{60}}=$$
$$=\frac{-\sin\ang{60}}{1+\sin\ang{60}}=-\frac{\frac{1}{2}}{1+\frac{\sqrt{3}}{2}}
- =-\frac{1}{2\left(\frac{\sqrt{3}}{2}+1\right)}=\frac{1}{2\cdot\frac{\sqrt{3}+2}{2}}=-\frac{1}{2\left(\sqrt{3}+2\right)}
- =\frac{1}{\sqrt{3}+2}=\frac{2-\sqrt{3}}{\left(\sqrt{3}+2\right)\left(\sqrt{2-\sqrt{3}}\right)}=$$
- $$=2-\sqrt{3}$$
+ =-\frac{1}{2\left(\frac{\sqrt{3}}{2}+1\right)}=-\frac{1}{2\cdot\frac{\sqrt{3}+2}{2}}=-\frac{1}{2\left(\sqrt{3}+2\right)}
+ =-\frac{1}{\sqrt{3}+2}=-\frac{2-\sqrt{3}}{\left(\sqrt{3}+2\right)\left(\sqrt{2-\sqrt{3}}\right)}=$$
+ $$=\sqrt{3}-2$$
\end{enumerate}
\item Naj bo $\alpha$ kot, za katerega velja $\ang{0}\leq\alpha\leq\ang{360}$. V enotskem krogu načrtaj in nato še zapiši v stopinjah vse velikosti kotov $\alpha$, za katere velja:
\begin{enumerate}[label=\textbf{\xslalph*)}]